3.3.73 \(\int (d+e x)^3 (b x+c x^2)^{3/2} \, dx\)

Optimal. Leaf size=271 \[ -\frac {3 b^2 (b+2 c x) \sqrt {b x+c x^2} (2 c d-b e) \left (3 b^2 e^2-8 b c d e+8 c^2 d^2\right )}{1024 c^5}+\frac {(b+2 c x) \left (b x+c x^2\right )^{3/2} (2 c d-b e) \left (3 b^2 e^2-8 b c d e+8 c^2 d^2\right )}{128 c^4}+\frac {e \left (b x+c x^2\right )^{5/2} \left (21 b^2 e^2+30 c e x (2 c d-b e)-98 b c d e+128 c^2 d^2\right )}{280 c^3}+\frac {3 b^4 (2 c d-b e) \left (3 b^2 e^2-8 b c d e+8 c^2 d^2\right ) \tanh ^{-1}\left (\frac {\sqrt {c} x}{\sqrt {b x+c x^2}}\right )}{1024 c^{11/2}}+\frac {e \left (b x+c x^2\right )^{5/2} (d+e x)^2}{7 c} \]

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Rubi [A]  time = 0.35, antiderivative size = 271, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 5, integrand size = 21, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.238, Rules used = {742, 779, 612, 620, 206} \begin {gather*} -\frac {3 b^2 (b+2 c x) \sqrt {b x+c x^2} (2 c d-b e) \left (3 b^2 e^2-8 b c d e+8 c^2 d^2\right )}{1024 c^5}+\frac {e \left (b x+c x^2\right )^{5/2} \left (21 b^2 e^2+30 c e x (2 c d-b e)-98 b c d e+128 c^2 d^2\right )}{280 c^3}+\frac {(b+2 c x) \left (b x+c x^2\right )^{3/2} (2 c d-b e) \left (3 b^2 e^2-8 b c d e+8 c^2 d^2\right )}{128 c^4}+\frac {3 b^4 (2 c d-b e) \left (3 b^2 e^2-8 b c d e+8 c^2 d^2\right ) \tanh ^{-1}\left (\frac {\sqrt {c} x}{\sqrt {b x+c x^2}}\right )}{1024 c^{11/2}}+\frac {e \left (b x+c x^2\right )^{5/2} (d+e x)^2}{7 c} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[(d + e*x)^3*(b*x + c*x^2)^(3/2),x]

[Out]

(-3*b^2*(2*c*d - b*e)*(8*c^2*d^2 - 8*b*c*d*e + 3*b^2*e^2)*(b + 2*c*x)*Sqrt[b*x + c*x^2])/(1024*c^5) + ((2*c*d
- b*e)*(8*c^2*d^2 - 8*b*c*d*e + 3*b^2*e^2)*(b + 2*c*x)*(b*x + c*x^2)^(3/2))/(128*c^4) + (e*(d + e*x)^2*(b*x +
c*x^2)^(5/2))/(7*c) + (e*(128*c^2*d^2 - 98*b*c*d*e + 21*b^2*e^2 + 30*c*e*(2*c*d - b*e)*x)*(b*x + c*x^2)^(5/2))
/(280*c^3) + (3*b^4*(2*c*d - b*e)*(8*c^2*d^2 - 8*b*c*d*e + 3*b^2*e^2)*ArcTanh[(Sqrt[c]*x)/Sqrt[b*x + c*x^2]])/
(1024*c^(11/2))

Rule 206

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1*ArcTanh[(Rt[-b, 2]*x)/Rt[a, 2]])/(Rt[a, 2]*Rt[-b, 2]), x]
/; FreeQ[{a, b}, x] && NegQ[a/b] && (GtQ[a, 0] || LtQ[b, 0])

Rule 612

Int[((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_), x_Symbol] :> Simp[((b + 2*c*x)*(a + b*x + c*x^2)^p)/(2*c*(2*p +
1)), x] - Dist[(p*(b^2 - 4*a*c))/(2*c*(2*p + 1)), Int[(a + b*x + c*x^2)^(p - 1), x], x] /; FreeQ[{a, b, c}, x]
&& NeQ[b^2 - 4*a*c, 0] && GtQ[p, 0] && IntegerQ[4*p]

Rule 620

Int[1/Sqrt[(b_.)*(x_) + (c_.)*(x_)^2], x_Symbol] :> Dist[2, Subst[Int[1/(1 - c*x^2), x], x, x/Sqrt[b*x + c*x^2
]], x] /; FreeQ[{b, c}, x]

Rule 742

Int[((d_.) + (e_.)*(x_))^(m_)*((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_), x_Symbol] :> Simp[(e*(d + e*x)^(m - 1)
*(a + b*x + c*x^2)^(p + 1))/(c*(m + 2*p + 1)), x] + Dist[1/(c*(m + 2*p + 1)), Int[(d + e*x)^(m - 2)*Simp[c*d^2
*(m + 2*p + 1) - e*(a*e*(m - 1) + b*d*(p + 1)) + e*(2*c*d - b*e)*(m + p)*x, x]*(a + b*x + c*x^2)^p, x], x] /;
FreeQ[{a, b, c, d, e, m, p}, x] && NeQ[b^2 - 4*a*c, 0] && NeQ[c*d^2 - b*d*e + a*e^2, 0] && NeQ[2*c*d - b*e, 0]
&& If[RationalQ[m], GtQ[m, 1], SumSimplerQ[m, -2]] && NeQ[m + 2*p + 1, 0] && IntQuadraticQ[a, b, c, d, e, m,
p, x]

Rule 779

Int[((d_.) + (e_.)*(x_))*((f_.) + (g_.)*(x_))*((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_), x_Symbol] :> -Simp[((b
*e*g*(p + 2) - c*(e*f + d*g)*(2*p + 3) - 2*c*e*g*(p + 1)*x)*(a + b*x + c*x^2)^(p + 1))/(2*c^2*(p + 1)*(2*p + 3
)), x] + Dist[(b^2*e*g*(p + 2) - 2*a*c*e*g + c*(2*c*d*f - b*(e*f + d*g))*(2*p + 3))/(2*c^2*(2*p + 3)), Int[(a
+ b*x + c*x^2)^p, x], x] /; FreeQ[{a, b, c, d, e, f, g, p}, x] && NeQ[b^2 - 4*a*c, 0] &&  !LeQ[p, -1]

Rubi steps

\begin {align*} \int (d+e x)^3 \left (b x+c x^2\right )^{3/2} \, dx &=\frac {e (d+e x)^2 \left (b x+c x^2\right )^{5/2}}{7 c}+\frac {\int (d+e x) \left (\frac {1}{2} d (14 c d-5 b e)+\frac {9}{2} e (2 c d-b e) x\right ) \left (b x+c x^2\right )^{3/2} \, dx}{7 c}\\ &=\frac {e (d+e x)^2 \left (b x+c x^2\right )^{5/2}}{7 c}+\frac {e \left (128 c^2 d^2-98 b c d e+21 b^2 e^2+30 c e (2 c d-b e) x\right ) \left (b x+c x^2\right )^{5/2}}{280 c^3}+\frac {\left ((2 c d-b e) \left (8 c^2 d^2-8 b c d e+3 b^2 e^2\right )\right ) \int \left (b x+c x^2\right )^{3/2} \, dx}{16 c^3}\\ &=\frac {(2 c d-b e) \left (8 c^2 d^2-8 b c d e+3 b^2 e^2\right ) (b+2 c x) \left (b x+c x^2\right )^{3/2}}{128 c^4}+\frac {e (d+e x)^2 \left (b x+c x^2\right )^{5/2}}{7 c}+\frac {e \left (128 c^2 d^2-98 b c d e+21 b^2 e^2+30 c e (2 c d-b e) x\right ) \left (b x+c x^2\right )^{5/2}}{280 c^3}-\frac {\left (3 b^2 (2 c d-b e) \left (8 c^2 d^2-8 b c d e+3 b^2 e^2\right )\right ) \int \sqrt {b x+c x^2} \, dx}{256 c^4}\\ &=-\frac {3 b^2 (2 c d-b e) \left (8 c^2 d^2-8 b c d e+3 b^2 e^2\right ) (b+2 c x) \sqrt {b x+c x^2}}{1024 c^5}+\frac {(2 c d-b e) \left (8 c^2 d^2-8 b c d e+3 b^2 e^2\right ) (b+2 c x) \left (b x+c x^2\right )^{3/2}}{128 c^4}+\frac {e (d+e x)^2 \left (b x+c x^2\right )^{5/2}}{7 c}+\frac {e \left (128 c^2 d^2-98 b c d e+21 b^2 e^2+30 c e (2 c d-b e) x\right ) \left (b x+c x^2\right )^{5/2}}{280 c^3}+\frac {\left (3 b^4 (2 c d-b e) \left (8 c^2 d^2-8 b c d e+3 b^2 e^2\right )\right ) \int \frac {1}{\sqrt {b x+c x^2}} \, dx}{2048 c^5}\\ &=-\frac {3 b^2 (2 c d-b e) \left (8 c^2 d^2-8 b c d e+3 b^2 e^2\right ) (b+2 c x) \sqrt {b x+c x^2}}{1024 c^5}+\frac {(2 c d-b e) \left (8 c^2 d^2-8 b c d e+3 b^2 e^2\right ) (b+2 c x) \left (b x+c x^2\right )^{3/2}}{128 c^4}+\frac {e (d+e x)^2 \left (b x+c x^2\right )^{5/2}}{7 c}+\frac {e \left (128 c^2 d^2-98 b c d e+21 b^2 e^2+30 c e (2 c d-b e) x\right ) \left (b x+c x^2\right )^{5/2}}{280 c^3}+\frac {\left (3 b^4 (2 c d-b e) \left (8 c^2 d^2-8 b c d e+3 b^2 e^2\right )\right ) \operatorname {Subst}\left (\int \frac {1}{1-c x^2} \, dx,x,\frac {x}{\sqrt {b x+c x^2}}\right )}{1024 c^5}\\ &=-\frac {3 b^2 (2 c d-b e) \left (8 c^2 d^2-8 b c d e+3 b^2 e^2\right ) (b+2 c x) \sqrt {b x+c x^2}}{1024 c^5}+\frac {(2 c d-b e) \left (8 c^2 d^2-8 b c d e+3 b^2 e^2\right ) (b+2 c x) \left (b x+c x^2\right )^{3/2}}{128 c^4}+\frac {e (d+e x)^2 \left (b x+c x^2\right )^{5/2}}{7 c}+\frac {e \left (128 c^2 d^2-98 b c d e+21 b^2 e^2+30 c e (2 c d-b e) x\right ) \left (b x+c x^2\right )^{5/2}}{280 c^3}+\frac {3 b^4 (2 c d-b e) \left (8 c^2 d^2-8 b c d e+3 b^2 e^2\right ) \tanh ^{-1}\left (\frac {\sqrt {c} x}{\sqrt {b x+c x^2}}\right )}{1024 c^{11/2}}\\ \end {align*}

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Mathematica [A]  time = 0.68, size = 312, normalized size = 1.15 \begin {gather*} \frac {\sqrt {x (b+c x)} \left (\sqrt {c} \left (315 b^6 e^3-210 b^5 c e^2 (7 d+e x)+28 b^4 c^2 e \left (90 d^2+35 d e x+6 e^2 x^2\right )-16 b^3 c^3 \left (105 d^3+105 d^2 e x+49 d e^2 x^2+9 e^3 x^3\right )+32 b^2 c^4 x \left (35 d^3+42 d^2 e x+21 d e^2 x^2+4 e^3 x^3\right )+128 b c^5 x^2 \left (105 d^3+231 d^2 e x+182 d e^2 x^2+50 e^3 x^3\right )+256 c^6 x^3 \left (35 d^3+84 d^2 e x+70 d e^2 x^2+20 e^3 x^3\right )\right )-\frac {105 b^{7/2} \left (3 b^3 e^3-14 b^2 c d e^2+24 b c^2 d^2 e-16 c^3 d^3\right ) \sinh ^{-1}\left (\frac {\sqrt {c} \sqrt {x}}{\sqrt {b}}\right )}{\sqrt {x} \sqrt {\frac {c x}{b}+1}}\right )}{35840 c^{11/2}} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[(d + e*x)^3*(b*x + c*x^2)^(3/2),x]

[Out]

(Sqrt[x*(b + c*x)]*(Sqrt[c]*(315*b^6*e^3 - 210*b^5*c*e^2*(7*d + e*x) + 28*b^4*c^2*e*(90*d^2 + 35*d*e*x + 6*e^2
*x^2) + 32*b^2*c^4*x*(35*d^3 + 42*d^2*e*x + 21*d*e^2*x^2 + 4*e^3*x^3) - 16*b^3*c^3*(105*d^3 + 105*d^2*e*x + 49
*d*e^2*x^2 + 9*e^3*x^3) + 256*c^6*x^3*(35*d^3 + 84*d^2*e*x + 70*d*e^2*x^2 + 20*e^3*x^3) + 128*b*c^5*x^2*(105*d
^3 + 231*d^2*e*x + 182*d*e^2*x^2 + 50*e^3*x^3)) - (105*b^(7/2)*(-16*c^3*d^3 + 24*b*c^2*d^2*e - 14*b^2*c*d*e^2
+ 3*b^3*e^3)*ArcSinh[(Sqrt[c]*Sqrt[x])/Sqrt[b]])/(Sqrt[x]*Sqrt[1 + (c*x)/b])))/(35840*c^(11/2))

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IntegrateAlgebraic [A]  time = 1.21, size = 372, normalized size = 1.37 \begin {gather*} \frac {3 \left (3 b^7 e^3-14 b^6 c d e^2+24 b^5 c^2 d^2 e-16 b^4 c^3 d^3\right ) \log \left (-2 \sqrt {c} \sqrt {b x+c x^2}+b+2 c x\right )}{2048 c^{11/2}}+\frac {\sqrt {b x+c x^2} \left (315 b^6 e^3-1470 b^5 c d e^2-210 b^5 c e^3 x+2520 b^4 c^2 d^2 e+980 b^4 c^2 d e^2 x+168 b^4 c^2 e^3 x^2-1680 b^3 c^3 d^3-1680 b^3 c^3 d^2 e x-784 b^3 c^3 d e^2 x^2-144 b^3 c^3 e^3 x^3+1120 b^2 c^4 d^3 x+1344 b^2 c^4 d^2 e x^2+672 b^2 c^4 d e^2 x^3+128 b^2 c^4 e^3 x^4+13440 b c^5 d^3 x^2+29568 b c^5 d^2 e x^3+23296 b c^5 d e^2 x^4+6400 b c^5 e^3 x^5+8960 c^6 d^3 x^3+21504 c^6 d^2 e x^4+17920 c^6 d e^2 x^5+5120 c^6 e^3 x^6\right )}{35840 c^5} \end {gather*}

Antiderivative was successfully verified.

[In]

IntegrateAlgebraic[(d + e*x)^3*(b*x + c*x^2)^(3/2),x]

[Out]

(Sqrt[b*x + c*x^2]*(-1680*b^3*c^3*d^3 + 2520*b^4*c^2*d^2*e - 1470*b^5*c*d*e^2 + 315*b^6*e^3 + 1120*b^2*c^4*d^3
*x - 1680*b^3*c^3*d^2*e*x + 980*b^4*c^2*d*e^2*x - 210*b^5*c*e^3*x + 13440*b*c^5*d^3*x^2 + 1344*b^2*c^4*d^2*e*x
^2 - 784*b^3*c^3*d*e^2*x^2 + 168*b^4*c^2*e^3*x^2 + 8960*c^6*d^3*x^3 + 29568*b*c^5*d^2*e*x^3 + 672*b^2*c^4*d*e^
2*x^3 - 144*b^3*c^3*e^3*x^3 + 21504*c^6*d^2*e*x^4 + 23296*b*c^5*d*e^2*x^4 + 128*b^2*c^4*e^3*x^4 + 17920*c^6*d*
e^2*x^5 + 6400*b*c^5*e^3*x^5 + 5120*c^6*e^3*x^6))/(35840*c^5) + (3*(-16*b^4*c^3*d^3 + 24*b^5*c^2*d^2*e - 14*b^
6*c*d*e^2 + 3*b^7*e^3)*Log[b + 2*c*x - 2*Sqrt[c]*Sqrt[b*x + c*x^2]])/(2048*c^(11/2))

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fricas [A]  time = 0.45, size = 706, normalized size = 2.61 \begin {gather*} \left [-\frac {105 \, {\left (16 \, b^{4} c^{3} d^{3} - 24 \, b^{5} c^{2} d^{2} e + 14 \, b^{6} c d e^{2} - 3 \, b^{7} e^{3}\right )} \sqrt {c} \log \left (2 \, c x + b - 2 \, \sqrt {c x^{2} + b x} \sqrt {c}\right ) - 2 \, {\left (5120 \, c^{7} e^{3} x^{6} - 1680 \, b^{3} c^{4} d^{3} + 2520 \, b^{4} c^{3} d^{2} e - 1470 \, b^{5} c^{2} d e^{2} + 315 \, b^{6} c e^{3} + 1280 \, {\left (14 \, c^{7} d e^{2} + 5 \, b c^{6} e^{3}\right )} x^{5} + 128 \, {\left (168 \, c^{7} d^{2} e + 182 \, b c^{6} d e^{2} + b^{2} c^{5} e^{3}\right )} x^{4} + 16 \, {\left (560 \, c^{7} d^{3} + 1848 \, b c^{6} d^{2} e + 42 \, b^{2} c^{5} d e^{2} - 9 \, b^{3} c^{4} e^{3}\right )} x^{3} + 56 \, {\left (240 \, b c^{6} d^{3} + 24 \, b^{2} c^{5} d^{2} e - 14 \, b^{3} c^{4} d e^{2} + 3 \, b^{4} c^{3} e^{3}\right )} x^{2} + 70 \, {\left (16 \, b^{2} c^{5} d^{3} - 24 \, b^{3} c^{4} d^{2} e + 14 \, b^{4} c^{3} d e^{2} - 3 \, b^{5} c^{2} e^{3}\right )} x\right )} \sqrt {c x^{2} + b x}}{71680 \, c^{6}}, -\frac {105 \, {\left (16 \, b^{4} c^{3} d^{3} - 24 \, b^{5} c^{2} d^{2} e + 14 \, b^{6} c d e^{2} - 3 \, b^{7} e^{3}\right )} \sqrt {-c} \arctan \left (\frac {\sqrt {c x^{2} + b x} \sqrt {-c}}{c x}\right ) - {\left (5120 \, c^{7} e^{3} x^{6} - 1680 \, b^{3} c^{4} d^{3} + 2520 \, b^{4} c^{3} d^{2} e - 1470 \, b^{5} c^{2} d e^{2} + 315 \, b^{6} c e^{3} + 1280 \, {\left (14 \, c^{7} d e^{2} + 5 \, b c^{6} e^{3}\right )} x^{5} + 128 \, {\left (168 \, c^{7} d^{2} e + 182 \, b c^{6} d e^{2} + b^{2} c^{5} e^{3}\right )} x^{4} + 16 \, {\left (560 \, c^{7} d^{3} + 1848 \, b c^{6} d^{2} e + 42 \, b^{2} c^{5} d e^{2} - 9 \, b^{3} c^{4} e^{3}\right )} x^{3} + 56 \, {\left (240 \, b c^{6} d^{3} + 24 \, b^{2} c^{5} d^{2} e - 14 \, b^{3} c^{4} d e^{2} + 3 \, b^{4} c^{3} e^{3}\right )} x^{2} + 70 \, {\left (16 \, b^{2} c^{5} d^{3} - 24 \, b^{3} c^{4} d^{2} e + 14 \, b^{4} c^{3} d e^{2} - 3 \, b^{5} c^{2} e^{3}\right )} x\right )} \sqrt {c x^{2} + b x}}{35840 \, c^{6}}\right ] \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((e*x+d)^3*(c*x^2+b*x)^(3/2),x, algorithm="fricas")

[Out]

[-1/71680*(105*(16*b^4*c^3*d^3 - 24*b^5*c^2*d^2*e + 14*b^6*c*d*e^2 - 3*b^7*e^3)*sqrt(c)*log(2*c*x + b - 2*sqrt
(c*x^2 + b*x)*sqrt(c)) - 2*(5120*c^7*e^3*x^6 - 1680*b^3*c^4*d^3 + 2520*b^4*c^3*d^2*e - 1470*b^5*c^2*d*e^2 + 31
5*b^6*c*e^3 + 1280*(14*c^7*d*e^2 + 5*b*c^6*e^3)*x^5 + 128*(168*c^7*d^2*e + 182*b*c^6*d*e^2 + b^2*c^5*e^3)*x^4
+ 16*(560*c^7*d^3 + 1848*b*c^6*d^2*e + 42*b^2*c^5*d*e^2 - 9*b^3*c^4*e^3)*x^3 + 56*(240*b*c^6*d^3 + 24*b^2*c^5*
d^2*e - 14*b^3*c^4*d*e^2 + 3*b^4*c^3*e^3)*x^2 + 70*(16*b^2*c^5*d^3 - 24*b^3*c^4*d^2*e + 14*b^4*c^3*d*e^2 - 3*b
^5*c^2*e^3)*x)*sqrt(c*x^2 + b*x))/c^6, -1/35840*(105*(16*b^4*c^3*d^3 - 24*b^5*c^2*d^2*e + 14*b^6*c*d*e^2 - 3*b
^7*e^3)*sqrt(-c)*arctan(sqrt(c*x^2 + b*x)*sqrt(-c)/(c*x)) - (5120*c^7*e^3*x^6 - 1680*b^3*c^4*d^3 + 2520*b^4*c^
3*d^2*e - 1470*b^5*c^2*d*e^2 + 315*b^6*c*e^3 + 1280*(14*c^7*d*e^2 + 5*b*c^6*e^3)*x^5 + 128*(168*c^7*d^2*e + 18
2*b*c^6*d*e^2 + b^2*c^5*e^3)*x^4 + 16*(560*c^7*d^3 + 1848*b*c^6*d^2*e + 42*b^2*c^5*d*e^2 - 9*b^3*c^4*e^3)*x^3
+ 56*(240*b*c^6*d^3 + 24*b^2*c^5*d^2*e - 14*b^3*c^4*d*e^2 + 3*b^4*c^3*e^3)*x^2 + 70*(16*b^2*c^5*d^3 - 24*b^3*c
^4*d^2*e + 14*b^4*c^3*d*e^2 - 3*b^5*c^2*e^3)*x)*sqrt(c*x^2 + b*x))/c^6]

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giac [A]  time = 0.24, size = 365, normalized size = 1.35 \begin {gather*} \frac {1}{35840} \, \sqrt {c x^{2} + b x} {\left (2 \, {\left (4 \, {\left (2 \, {\left (8 \, {\left (10 \, {\left (4 \, c x e^{3} + \frac {14 \, c^{7} d e^{2} + 5 \, b c^{6} e^{3}}{c^{6}}\right )} x + \frac {168 \, c^{7} d^{2} e + 182 \, b c^{6} d e^{2} + b^{2} c^{5} e^{3}}{c^{6}}\right )} x + \frac {560 \, c^{7} d^{3} + 1848 \, b c^{6} d^{2} e + 42 \, b^{2} c^{5} d e^{2} - 9 \, b^{3} c^{4} e^{3}}{c^{6}}\right )} x + \frac {7 \, {\left (240 \, b c^{6} d^{3} + 24 \, b^{2} c^{5} d^{2} e - 14 \, b^{3} c^{4} d e^{2} + 3 \, b^{4} c^{3} e^{3}\right )}}{c^{6}}\right )} x + \frac {35 \, {\left (16 \, b^{2} c^{5} d^{3} - 24 \, b^{3} c^{4} d^{2} e + 14 \, b^{4} c^{3} d e^{2} - 3 \, b^{5} c^{2} e^{3}\right )}}{c^{6}}\right )} x - \frac {105 \, {\left (16 \, b^{3} c^{4} d^{3} - 24 \, b^{4} c^{3} d^{2} e + 14 \, b^{5} c^{2} d e^{2} - 3 \, b^{6} c e^{3}\right )}}{c^{6}}\right )} - \frac {3 \, {\left (16 \, b^{4} c^{3} d^{3} - 24 \, b^{5} c^{2} d^{2} e + 14 \, b^{6} c d e^{2} - 3 \, b^{7} e^{3}\right )} \log \left ({\left | -2 \, {\left (\sqrt {c} x - \sqrt {c x^{2} + b x}\right )} \sqrt {c} - b \right |}\right )}{2048 \, c^{\frac {11}{2}}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((e*x+d)^3*(c*x^2+b*x)^(3/2),x, algorithm="giac")

[Out]

1/35840*sqrt(c*x^2 + b*x)*(2*(4*(2*(8*(10*(4*c*x*e^3 + (14*c^7*d*e^2 + 5*b*c^6*e^3)/c^6)*x + (168*c^7*d^2*e +
182*b*c^6*d*e^2 + b^2*c^5*e^3)/c^6)*x + (560*c^7*d^3 + 1848*b*c^6*d^2*e + 42*b^2*c^5*d*e^2 - 9*b^3*c^4*e^3)/c^
6)*x + 7*(240*b*c^6*d^3 + 24*b^2*c^5*d^2*e - 14*b^3*c^4*d*e^2 + 3*b^4*c^3*e^3)/c^6)*x + 35*(16*b^2*c^5*d^3 - 2
4*b^3*c^4*d^2*e + 14*b^4*c^3*d*e^2 - 3*b^5*c^2*e^3)/c^6)*x - 105*(16*b^3*c^4*d^3 - 24*b^4*c^3*d^2*e + 14*b^5*c
^2*d*e^2 - 3*b^6*c*e^3)/c^6) - 3/2048*(16*b^4*c^3*d^3 - 24*b^5*c^2*d^2*e + 14*b^6*c*d*e^2 - 3*b^7*e^3)*log(abs
(-2*(sqrt(c)*x - sqrt(c*x^2 + b*x))*sqrt(c) - b))/c^(11/2)

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maple [B]  time = 0.05, size = 629, normalized size = 2.32 \begin {gather*} -\frac {9 b^{7} e^{3} \ln \left (\frac {c x +\frac {b}{2}}{\sqrt {c}}+\sqrt {c \,x^{2}+b x}\right )}{2048 c^{\frac {11}{2}}}+\frac {21 b^{6} d \,e^{2} \ln \left (\frac {c x +\frac {b}{2}}{\sqrt {c}}+\sqrt {c \,x^{2}+b x}\right )}{1024 c^{\frac {9}{2}}}-\frac {9 b^{5} d^{2} e \ln \left (\frac {c x +\frac {b}{2}}{\sqrt {c}}+\sqrt {c \,x^{2}+b x}\right )}{256 c^{\frac {7}{2}}}+\frac {3 b^{4} d^{3} \ln \left (\frac {c x +\frac {b}{2}}{\sqrt {c}}+\sqrt {c \,x^{2}+b x}\right )}{128 c^{\frac {5}{2}}}+\frac {9 \sqrt {c \,x^{2}+b x}\, b^{5} e^{3} x}{512 c^{4}}-\frac {21 \sqrt {c \,x^{2}+b x}\, b^{4} d \,e^{2} x}{256 c^{3}}+\frac {9 \sqrt {c \,x^{2}+b x}\, b^{3} d^{2} e x}{64 c^{2}}-\frac {3 \sqrt {c \,x^{2}+b x}\, b^{2} d^{3} x}{32 c}+\frac {9 \sqrt {c \,x^{2}+b x}\, b^{6} e^{3}}{1024 c^{5}}-\frac {21 \sqrt {c \,x^{2}+b x}\, b^{5} d \,e^{2}}{512 c^{4}}+\frac {9 \sqrt {c \,x^{2}+b x}\, b^{4} d^{2} e}{128 c^{3}}-\frac {3 \sqrt {c \,x^{2}+b x}\, b^{3} d^{3}}{64 c^{2}}-\frac {3 \left (c \,x^{2}+b x \right )^{\frac {3}{2}} b^{3} e^{3} x}{64 c^{3}}+\frac {7 \left (c \,x^{2}+b x \right )^{\frac {3}{2}} b^{2} d \,e^{2} x}{32 c^{2}}-\frac {3 \left (c \,x^{2}+b x \right )^{\frac {3}{2}} b \,d^{2} e x}{8 c}+\frac {\left (c \,x^{2}+b x \right )^{\frac {5}{2}} e^{3} x^{2}}{7 c}+\frac {\left (c \,x^{2}+b x \right )^{\frac {3}{2}} d^{3} x}{4}-\frac {3 \left (c \,x^{2}+b x \right )^{\frac {3}{2}} b^{4} e^{3}}{128 c^{4}}+\frac {7 \left (c \,x^{2}+b x \right )^{\frac {3}{2}} b^{3} d \,e^{2}}{64 c^{3}}-\frac {3 \left (c \,x^{2}+b x \right )^{\frac {3}{2}} b^{2} d^{2} e}{16 c^{2}}+\frac {\left (c \,x^{2}+b x \right )^{\frac {3}{2}} b \,d^{3}}{8 c}-\frac {3 \left (c \,x^{2}+b x \right )^{\frac {5}{2}} b \,e^{3} x}{28 c^{2}}+\frac {\left (c \,x^{2}+b x \right )^{\frac {5}{2}} d \,e^{2} x}{2 c}+\frac {3 \left (c \,x^{2}+b x \right )^{\frac {5}{2}} b^{2} e^{3}}{40 c^{3}}-\frac {7 \left (c \,x^{2}+b x \right )^{\frac {5}{2}} b d \,e^{2}}{20 c^{2}}+\frac {3 \left (c \,x^{2}+b x \right )^{\frac {5}{2}} d^{2} e}{5 c} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((e*x+d)^3*(c*x^2+b*x)^(3/2),x)

[Out]

3/128*d^3*b^4/c^(5/2)*ln((c*x+1/2*b)/c^(1/2)+(c*x^2+b*x)^(1/2))+3/5*d^2*e*(c*x^2+b*x)^(5/2)/c-3/128*e^3*b^4/c^
4*(c*x^2+b*x)^(3/2)+9/1024*e^3*b^6/c^5*(c*x^2+b*x)^(1/2)-9/2048*e^3*b^7/c^(11/2)*ln((c*x+1/2*b)/c^(1/2)+(c*x^2
+b*x)^(1/2))+1/7*e^3*x^2*(c*x^2+b*x)^(5/2)/c+3/40*e^3*b^2/c^3*(c*x^2+b*x)^(5/2)+1/8*d^3/c*(c*x^2+b*x)^(3/2)*b-
3/64*d^3*b^3/c^2*(c*x^2+b*x)^(1/2)+7/32*d*e^2*b^2/c^2*x*(c*x^2+b*x)^(3/2)-21/256*d*e^2*b^4/c^3*(c*x^2+b*x)^(1/
2)*x+9/64*d^2*e*b^3/c^2*(c*x^2+b*x)^(1/2)*x-3/8*d^2*e*b/c*x*(c*x^2+b*x)^(3/2)-3/16*d^2*e*b^2/c^2*(c*x^2+b*x)^(
3/2)+1/4*d^3*x*(c*x^2+b*x)^(3/2)+9/512*e^3*b^5/c^4*(c*x^2+b*x)^(1/2)*x-3/32*d^3*b^2/c*(c*x^2+b*x)^(1/2)*x-3/64
*e^3*b^3/c^3*x*(c*x^2+b*x)^(3/2)+9/128*d^2*e*b^4/c^3*(c*x^2+b*x)^(1/2)-9/256*d^2*e*b^5/c^(7/2)*ln((c*x+1/2*b)/
c^(1/2)+(c*x^2+b*x)^(1/2))-21/512*d*e^2*b^5/c^4*(c*x^2+b*x)^(1/2)+1/2*d*e^2*x*(c*x^2+b*x)^(5/2)/c+21/1024*d*e^
2*b^6/c^(9/2)*ln((c*x+1/2*b)/c^(1/2)+(c*x^2+b*x)^(1/2))-3/28*e^3*b/c^2*x*(c*x^2+b*x)^(5/2)-7/20*d*e^2*b/c^2*(c
*x^2+b*x)^(5/2)+7/64*d*e^2*b^3/c^3*(c*x^2+b*x)^(3/2)

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maxima [B]  time = 1.48, size = 624, normalized size = 2.30 \begin {gather*} \frac {{\left (c x^{2} + b x\right )}^{\frac {5}{2}} e^{3} x^{2}}{7 \, c} + \frac {1}{4} \, {\left (c x^{2} + b x\right )}^{\frac {3}{2}} d^{3} x - \frac {3 \, \sqrt {c x^{2} + b x} b^{2} d^{3} x}{32 \, c} + \frac {9 \, \sqrt {c x^{2} + b x} b^{3} d^{2} e x}{64 \, c^{2}} - \frac {3 \, {\left (c x^{2} + b x\right )}^{\frac {3}{2}} b d^{2} e x}{8 \, c} - \frac {21 \, \sqrt {c x^{2} + b x} b^{4} d e^{2} x}{256 \, c^{3}} + \frac {7 \, {\left (c x^{2} + b x\right )}^{\frac {3}{2}} b^{2} d e^{2} x}{32 \, c^{2}} + \frac {{\left (c x^{2} + b x\right )}^{\frac {5}{2}} d e^{2} x}{2 \, c} + \frac {9 \, \sqrt {c x^{2} + b x} b^{5} e^{3} x}{512 \, c^{4}} - \frac {3 \, {\left (c x^{2} + b x\right )}^{\frac {3}{2}} b^{3} e^{3} x}{64 \, c^{3}} - \frac {3 \, {\left (c x^{2} + b x\right )}^{\frac {5}{2}} b e^{3} x}{28 \, c^{2}} + \frac {3 \, b^{4} d^{3} \log \left (2 \, c x + b + 2 \, \sqrt {c x^{2} + b x} \sqrt {c}\right )}{128 \, c^{\frac {5}{2}}} - \frac {9 \, b^{5} d^{2} e \log \left (2 \, c x + b + 2 \, \sqrt {c x^{2} + b x} \sqrt {c}\right )}{256 \, c^{\frac {7}{2}}} + \frac {21 \, b^{6} d e^{2} \log \left (2 \, c x + b + 2 \, \sqrt {c x^{2} + b x} \sqrt {c}\right )}{1024 \, c^{\frac {9}{2}}} - \frac {9 \, b^{7} e^{3} \log \left (2 \, c x + b + 2 \, \sqrt {c x^{2} + b x} \sqrt {c}\right )}{2048 \, c^{\frac {11}{2}}} - \frac {3 \, \sqrt {c x^{2} + b x} b^{3} d^{3}}{64 \, c^{2}} + \frac {{\left (c x^{2} + b x\right )}^{\frac {3}{2}} b d^{3}}{8 \, c} + \frac {9 \, \sqrt {c x^{2} + b x} b^{4} d^{2} e}{128 \, c^{3}} - \frac {3 \, {\left (c x^{2} + b x\right )}^{\frac {3}{2}} b^{2} d^{2} e}{16 \, c^{2}} + \frac {3 \, {\left (c x^{2} + b x\right )}^{\frac {5}{2}} d^{2} e}{5 \, c} - \frac {21 \, \sqrt {c x^{2} + b x} b^{5} d e^{2}}{512 \, c^{4}} + \frac {7 \, {\left (c x^{2} + b x\right )}^{\frac {3}{2}} b^{3} d e^{2}}{64 \, c^{3}} - \frac {7 \, {\left (c x^{2} + b x\right )}^{\frac {5}{2}} b d e^{2}}{20 \, c^{2}} + \frac {9 \, \sqrt {c x^{2} + b x} b^{6} e^{3}}{1024 \, c^{5}} - \frac {3 \, {\left (c x^{2} + b x\right )}^{\frac {3}{2}} b^{4} e^{3}}{128 \, c^{4}} + \frac {3 \, {\left (c x^{2} + b x\right )}^{\frac {5}{2}} b^{2} e^{3}}{40 \, c^{3}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((e*x+d)^3*(c*x^2+b*x)^(3/2),x, algorithm="maxima")

[Out]

1/7*(c*x^2 + b*x)^(5/2)*e^3*x^2/c + 1/4*(c*x^2 + b*x)^(3/2)*d^3*x - 3/32*sqrt(c*x^2 + b*x)*b^2*d^3*x/c + 9/64*
sqrt(c*x^2 + b*x)*b^3*d^2*e*x/c^2 - 3/8*(c*x^2 + b*x)^(3/2)*b*d^2*e*x/c - 21/256*sqrt(c*x^2 + b*x)*b^4*d*e^2*x
/c^3 + 7/32*(c*x^2 + b*x)^(3/2)*b^2*d*e^2*x/c^2 + 1/2*(c*x^2 + b*x)^(5/2)*d*e^2*x/c + 9/512*sqrt(c*x^2 + b*x)*
b^5*e^3*x/c^4 - 3/64*(c*x^2 + b*x)^(3/2)*b^3*e^3*x/c^3 - 3/28*(c*x^2 + b*x)^(5/2)*b*e^3*x/c^2 + 3/128*b^4*d^3*
log(2*c*x + b + 2*sqrt(c*x^2 + b*x)*sqrt(c))/c^(5/2) - 9/256*b^5*d^2*e*log(2*c*x + b + 2*sqrt(c*x^2 + b*x)*sqr
t(c))/c^(7/2) + 21/1024*b^6*d*e^2*log(2*c*x + b + 2*sqrt(c*x^2 + b*x)*sqrt(c))/c^(9/2) - 9/2048*b^7*e^3*log(2*
c*x + b + 2*sqrt(c*x^2 + b*x)*sqrt(c))/c^(11/2) - 3/64*sqrt(c*x^2 + b*x)*b^3*d^3/c^2 + 1/8*(c*x^2 + b*x)^(3/2)
*b*d^3/c + 9/128*sqrt(c*x^2 + b*x)*b^4*d^2*e/c^3 - 3/16*(c*x^2 + b*x)^(3/2)*b^2*d^2*e/c^2 + 3/5*(c*x^2 + b*x)^
(5/2)*d^2*e/c - 21/512*sqrt(c*x^2 + b*x)*b^5*d*e^2/c^4 + 7/64*(c*x^2 + b*x)^(3/2)*b^3*d*e^2/c^3 - 7/20*(c*x^2
+ b*x)^(5/2)*b*d*e^2/c^2 + 9/1024*sqrt(c*x^2 + b*x)*b^6*e^3/c^5 - 3/128*(c*x^2 + b*x)^(3/2)*b^4*e^3/c^4 + 3/40
*(c*x^2 + b*x)^(5/2)*b^2*e^3/c^3

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mupad [F]  time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int {\left (c\,x^2+b\,x\right )}^{3/2}\,{\left (d+e\,x\right )}^3 \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((b*x + c*x^2)^(3/2)*(d + e*x)^3,x)

[Out]

int((b*x + c*x^2)^(3/2)*(d + e*x)^3, x)

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \left (x \left (b + c x\right )\right )^{\frac {3}{2}} \left (d + e x\right )^{3}\, dx \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((e*x+d)**3*(c*x**2+b*x)**(3/2),x)

[Out]

Integral((x*(b + c*x))**(3/2)*(d + e*x)**3, x)

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